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Potential difference between the points A and B in the circuit shown is 16 V, then potential difference across `2Omega` resistor is …. Volt. `(V_(A)gtV_(B))`

Text Solution

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`E_(eq) =((9)/(1)+(0)/(2))/((1)/(1)+(1)/(2))=9 div (3)/(2)=6` Volt
P.d. across `2 Omega =6V`
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