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Molar conductance of 0.1 M acetic acid i...

Molar conductance of 0.1 M acetic acid is 7 `ohm^(-1) cm^(2) "mol"^(-1)`. If the molar conductance of acetic acid at infinite dilution is 280 `ohm^(-1) cm^(2) "mol"^(-1)`, the value of dissoication constant will be:

Text Solution

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The correct Answer is:
1
`K_(a)=(c alpha^(2))/(1-alpha)" " …(i)`
`alpha=(lambda_(M)^(C ))/(lambda_(M)^(0)) " "…(ii)`
Solving Both (i) & (ii) gives `K_(a)=10^(-5)`
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