If `2cosx(4sin(pi/4+x) sin(pi/4-x)-1)=1` then for `x in [0,pi]` then the number of solution s is n ,and the sum of solutions is s then find the value of `(n,s)`

If x in[0,(pi)/(2)] then the number of solutions of the equation sin7x+sin4x+sin x=0 is

The number of solutions of |sin x|=tan x in [0,4 pi] is/are

If n is the number of solutions of the equation 2 cos x (4 sin ((pi)/4 + x ) sin ((pi)/4 - x) - 1) = 1, x in [ 0, pi] and S is the sum of all these solutions, then the ordered pair (n, S) is :

If n is the number of solutions of the equation 2 cos x (4 sin ((pi)/4 + x ) sin ((pi)/4 - x) - 1) = 1, x in [ 0, pi] and S is the sum of all these solutions, then the ordered pair (n, S) is :

The number of solutions of the equation sin2x-2cosx+4sinx=4 in the interval [0,5pi] is

If 1+sin^(2)(x)/(2)=0 then find the number of solution if x in [-pi,pi]

The number of solution of 2cosx=|sinx| where x in [0.4pi] is/are

find the number of solution of sin^(2) x-sin x-1=0 in [-2pi, 2pi] .