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A circular ground of radius 7 m is surro...

A circular ground of radius 7 m is surrounded by a path of width 3.5 m. Find the area of the path `(pi=(22)/(7))`

A

202 sq.m

B

154 sq.m

C

192.5sq.m

D

346 .5 sq. m

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The correct Answer is:
To find the area of the path surrounding the circular ground, we can follow these steps: ### Step 1: Determine the radius of the circular ground and the outer radius The radius of the circular ground is given as 7 m. The width of the path surrounding the circular ground is 3.5 m. Therefore, the outer radius (radius of the larger circle that includes the path) can be calculated as: \[ \text{Outer Radius} = \text{Radius of Circular Ground} + \text{Width of Path} \] \[ \text{Outer Radius} = 7 \, \text{m} + 3.5 \, \text{m} = 10.5 \, \text{m} \] ### Step 2: Calculate the area of the larger circle (including the path) The area \(A\) of a circle is given by the formula: \[ A = \pi r^2 \] Using the outer radius: \[ A_{\text{outer}} = \pi (10.5)^2 \] Substituting \(\pi = \frac{22}{7}\): \[ A_{\text{outer}} = \frac{22}{7} \times (10.5)^2 \] \[ A_{\text{outer}} = \frac{22}{7} \times 110.25 \] \[ A_{\text{outer}} = \frac{22 \times 110.25}{7} = \frac{2425.5}{7} = 346.5 \, \text{m}^2 \] ### Step 3: Calculate the area of the circular ground Now, we calculate the area of the circular ground: \[ A_{\text{inner}} = \pi (7)^2 \] \[ A_{\text{inner}} = \frac{22}{7} \times 49 \] \[ A_{\text{inner}} = \frac{1078}{7} = 154 \, \text{m}^2 \] ### Step 4: Calculate the area of the path The area of the path is the difference between the area of the larger circle and the area of the circular ground: \[ A_{\text{path}} = A_{\text{outer}} - A_{\text{inner}} \] \[ A_{\text{path}} = 346.5 \, \text{m}^2 - 154 \, \text{m}^2 = 192.5 \, \text{m}^2 \] ### Conclusion The area of the path surrounding the circular ground is \(192.5 \, \text{m}^2\).
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