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A woman invests Rs. 200 at the start of ...

A woman invests Rs. 200 at the start of each year at 5% compound interest per annum. How much will her investment be at the end of the `2^(nd)` year ?

A

431

B

`430.5`

C

435

D

430

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step-by-step, we need to calculate the total amount of investment at the end of the second year, considering the compound interest. ### Step 1: Calculate the amount from the first year's investment The woman invests Rs. 200 at the beginning of the first year. This amount will earn compound interest for 2 years at a rate of 5%. The formula for compound interest is: \[ A = P(1 + r)^n \] where: - \( A \) = the amount of money accumulated after n years, including interest. - \( P \) = principal amount (the initial amount of money). - \( r \) = annual interest rate (decimal). - \( n \) = number of years the money is invested or borrowed. For the first investment: - \( P = 200 \) - \( r = 5\% = 0.05 \) - \( n = 2 \) Substituting the values into the formula: \[ A = 200(1 + 0.05)^2 \] \[ A = 200(1.05)^2 \] \[ A = 200 \times 1.1025 \] \[ A = 220.5 \] ### Step 2: Calculate the amount from the second year's investment The woman invests another Rs. 200 at the beginning of the second year. This amount will earn interest for 1 year at the same rate of 5%. For the second investment: - \( P = 200 \) - \( r = 5\% = 0.05 \) - \( n = 1 \) Substituting the values into the formula: \[ A = 200(1 + 0.05)^1 \] \[ A = 200(1.05) \] \[ A = 200 \times 1.05 \] \[ A = 210 \] ### Step 3: Calculate the total amount at the end of the second year Now, we add the amounts from both investments: - Amount from the first investment after 2 years: Rs. 220.5 - Amount from the second investment after 1 year: Rs. 210 Total amount: \[ \text{Total Amount} = 220.5 + 210 = 430.5 \] Thus, the total investment at the end of the second year is **Rs. 430.5**.
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