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Kishlay travelled equal distances a spee...

Kishlay travelled equal distances a speeds of 10 km/hr, 30km/hr,and 2 km/hr and took a total time of 38 minutes. Find the total distance in km.

A

2

B

3

C

1

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow this approach: ### Step 1: Define the distance traveled Let the distance traveled in each case be \( x \) km. Since Kishlay traveled equal distances at three different speeds, we will calculate the time taken for each segment of the journey. ### Step 2: Calculate the time taken for each speed Using the formula for time, which is: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \] We can find the time taken for each speed: - For the speed of 10 km/hr: \[ \text{Time}_1 = \frac{x}{10} \text{ hours} \] - For the speed of 30 km/hr: \[ \text{Time}_2 = \frac{x}{30} \text{ hours} \] - For the speed of 2 km/hr: \[ \text{Time}_3 = \frac{x}{2} \text{ hours} \] ### Step 3: Set up the equation for total time The total time taken for the journey is given as 38 minutes. We need to convert this into hours: \[ 38 \text{ minutes} = \frac{38}{60} \text{ hours} \] Now, we can set up the equation: \[ \frac{x}{10} + \frac{x}{30} + \frac{x}{2} = \frac{38}{60} \] ### Step 4: Find a common denominator The least common multiple (LCM) of the denominators (10, 30, and 2) is 30. Rewriting each term with a common denominator: \[ \frac{3x}{30} + \frac{x}{30} + \frac{15x}{30} = \frac{38}{60} \] Combining the left side: \[ \frac{3x + x + 15x}{30} = \frac{38}{60} \] This simplifies to: \[ \frac{19x}{30} = \frac{38}{60} \] ### Step 5: Cross-multiply to solve for \( x \) Cross-multiplying gives: \[ 19x \cdot 60 = 38 \cdot 30 \] Calculating the right side: \[ 19x \cdot 60 = 1140 \] Now, divide both sides by 19: \[ x \cdot 60 = \frac{1140}{19} \] Calculating \( \frac{1140}{19} \): \[ x \cdot 60 = 60 \quad \Rightarrow \quad x = 1 \] ### Step 6: Calculate the total distance Since Kishlay traveled equal distances of \( x \) km in three segments, the total distance \( D \) is: \[ D = x + x + x = 3x = 3 \times 1 = 3 \text{ km} \] ### Final Answer The total distance traveled by Kishlay is **3 km**. ---
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