If A denotes `div`, B denotes `xx`, C denotes + and D denotes -, then 2 D 12 A 4 C 5 B 6 = -----------

Options

A. A. 29
B. B. 63
C. C. 36
D. D. 53

Answer

To solve the expression \( 2 D 12 A 4 C 5 B 6 \) where:
- \( A \) denotes division (\( \div \))
- \( B \) denotes multiplication (\( \times \))
- \( C \) denotes addition (\( + \))
- \( D \) denotes subtraction (\( - \))

We will follow these steps:

### Step 1: Replace the symbols with their respective operations
The expression can be rewritten as:
\[ 2 - 12 \div 4 + 5 \times 6 \]

### Step 2: Apply BODMAS/BIDMAS rules
According to the BODMAS/BIDMAS rules, we perform operations in the following order: Brackets, Orders (i.e., powers and square roots, etc.), Division and Multiplication (from left to right), Addition and Subtraction (from left to right).

### Step 3: Perform the division
First, we perform the division:
\[ 12 \div 4 = 3 \]
Now the expression becomes:
\[ 2 - 3 + 5 \times 6 \]

### Step 4: Perform the multiplication
Next, we perform the multiplication:
\[ 5 \times 6 = 30 \]
Now the expression becomes:
\[ 2 - 3 + 30 \]

### Step 5: Perform the subtraction and addition from left to right
Now, we perform the subtraction and addition:
1. First, calculate \( 2 - 3 \):
\[ 2 - 3 = -1 \]
2. Now add \( 30 \):
\[ -1 + 30 = 29 \]

### Final Answer
Thus, the final result of the expression \( 2 D 12 A 4 C 5 B 6 \) is:
\[ \boxed{29} \]