A porter lifts a luggage of 12 kg from the ground and puts it on his head 1.5 m above the ground. Calculate the work done by him on the luggage. `("g=10ms"^(-2))`

Options

A. a) 140 J
B. b) 180 J
C. c) 150 J
D. d) 155 J

Answer

To calculate the work done by the porter in lifting the luggage, we can follow these steps:

### Step 1: Understand the formula for work done
The work done (W) is calculated using the formula:
\[ W = F \times d \]
where:
- \( F \) is the force applied,
- \( d \) is the displacement in the direction of the force.

### Step 2: Identify the force applied
In this case, the force applied by the porter is equal to the weight of the luggage. The weight (force due to gravity) can be calculated using the formula:
\[ F = m \times g \]
where:
- \( m \) is the mass of the luggage (12 kg),
- \( g \) is the acceleration due to gravity (10 m/s²).

### Step 3: Calculate the weight of the luggage
Substituting the values into the formula:
\[ F = 12 \, \text{kg} \times 10 \, \text{m/s}^2 = 120 \, \text{N} \]

### Step 4: Determine the displacement
The displacement (height lifted) is given as 1.5 m.

### Step 5: Calculate the work done
Now that we have the force and the displacement, we can calculate the work done:
\[ W = F \times d = 120 \, \text{N} \times 1.5 \, \text{m} \]

### Step 6: Perform the multiplication
Calculating the above expression:
\[ W = 120 \times 1.5 = 180 \, \text{J} \]

### Final Answer
The work done by the porter on the luggage is:
\[ \text{Work Done} = 180 \, \text{Joules} \]

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