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Which signs should be interchanged if th...

Which signs should be interchanged if the equation below needs to be true?

`2 div 16-2 + 6 xx 1 = 0`

A. x and -

B. - and +

C. - and `div`

D. + and `xx`

A

D

B

C

C

B

D

A

Text Solution

AI Generated Solution

The correct Answer is:
To determine which signs should be interchanged in the equation `2 div 16 - 2 + 6 xx 1 = 0` to make it true, we will analyze each option step by step. ### Step 1: Write down the original equation The original equation is: \[ 2 \div 16 - 2 + 6 \times 1 = 0 \] ### Step 2: Evaluate the original equation Let's calculate the left-hand side of the equation: 1. Calculate \( 2 \div 16 \): \[ 2 \div 16 = 0.125 \] 2. Now substitute this value into the equation: \[ 0.125 - 2 + 6 \times 1 \] 3. Calculate \( 6 \times 1 \): \[ 6 \times 1 = 6 \] 4. Now substitute this value: \[ 0.125 - 2 + 6 = 0.125 - 2 + 6 \] 5. Combine the terms: \[ 0.125 - 2 = -1.875 \] \[ -1.875 + 6 = 4.125 \] The left-hand side evaluates to \( 4.125 \), which does not equal \( 0 \). ### Step 3: Test the options Now, we will test each option to see which one makes the equation true. #### Option A: Interchange `x` and `-` This means the equation becomes: \[ 2 \div 16 + 2 + 6 \times 1 \] Calculating: 1. \( 2 \div 16 = 0.125 \) 2. Substitute: \[ 0.125 + 2 + 6 = 0.125 + 2 + 6 = 8.125 \] This does not equal \( 0 \). #### Option B: Interchange `-` and `+` This means the equation becomes: \[ 2 \div 16 + 2 - 6 \times 1 \] Calculating: 1. \( 2 \div 16 = 0.125 \) 2. Substitute: \[ 0.125 + 2 - 6 = 0.125 + 2 - 6 = -3.875 \] This does not equal \( 0 \). #### Option C: Interchange `-` and `div` This means the equation becomes: \[ 2 - 16 \div 2 + 6 \times 1 \] Calculating: 1. \( 16 \div 2 = 8 \) 2. Substitute: \[ 2 - 8 + 6 = 2 - 8 + 6 = 0 \] This equals \( 0 \). #### Option D: Interchange `+` and `xx` This means the equation becomes: \[ 2 \div 16 - 2 + 6 \div 1 \] Calculating: 1. \( 6 \div 1 = 6 \) 2. Substitute: \[ 2 \div 16 - 2 + 6 = 0.125 - 2 + 6 = 4.125 \] This does not equal \( 0 \). ### Conclusion The correct option is **C**: Interchange `-` and `div`.
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