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Find the value of x if 0.08x+0.04y=10 a...

Find the value of x if `0.08x+0.04y=10 and 0.2(x-1)+0 .4y=24.8`
A. 125
B. 150
C.1.25
D. 12.5

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B

B

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C

D

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Text Solution

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The correct Answer is:
To solve the equations \(0.08x + 0.04y = 10\) and \(0.2(x - 1) + 0.4y = 24.8\), we will follow these steps: ### Step 1: Write down the equations We have the following two equations: 1. \(0.08x + 0.04y = 10\) (Equation 1) 2. \(0.2(x - 1) + 0.4y = 24.8\) (Equation 2) ### Step 2: Simplify Equation 2 First, we simplify Equation 2: \[ 0.2(x - 1) + 0.4y = 24.8 \] Distributing \(0.2\): \[ 0.2x - 0.2 + 0.4y = 24.8 \] Adding \(0.2\) to both sides: \[ 0.2x + 0.4y = 24.8 + 0.2 \] \[ 0.2x + 0.4y = 25 \] (Equation 2 simplified) ### Step 3: Eliminate \(y\) Now we have: 1. \(0.08x + 0.04y = 10\) (Equation 1) 2. \(0.2x + 0.4y = 25\) (Equation 2 simplified) To eliminate \(y\), we can multiply Equation 1 by \(10\) to make the coefficients of \(y\) the same: \[ 10(0.08x + 0.04y) = 10(10) \] This gives us: \[ 0.8x + 0.4y = 100 \quad (Equation 3) \] ### Step 4: Subtract the equations Now we have: 1. \(0.8x + 0.4y = 100\) (Equation 3) 2. \(0.2x + 0.4y = 25\) (Equation 2 simplified) We can subtract Equation 2 from Equation 3: \[ (0.8x + 0.4y) - (0.2x + 0.4y) = 100 - 25 \] The \(y\) terms cancel out: \[ 0.8x - 0.2x = 75 \] \[ 0.6x = 75 \] ### Step 5: Solve for \(x\) Now, divide both sides by \(0.6\): \[ x = \frac{75}{0.6} \] To eliminate the decimal, multiply the numerator and denominator by \(10\): \[ x = \frac{750}{6} \] Now, simplify: \[ x = 125 \] ### Conclusion The value of \(x\) is \(125\).
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