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If the length of the shadow of a vertica...

If the length of the shadow of a vertical pole on the horizontal ground is 3 times its height, then the angle of elevation
A `40^@`
B. `50^@`
C. `30^@`
D. `45^@`

A

C

B

D

C

A

D

B

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use trigonometric ratios to find the angle of elevation of the pole based on the given information about the shadow. ### Step-by-Step Solution: 1. **Understanding the Problem**: We have a vertical pole and the length of its shadow is given to be 3 times the height of the pole. Let the height of the pole be \( h \) and the length of the shadow be \( s \). According to the problem, we can express this relationship as: \[ s = 3h \] 2. **Setting Up the Triangle**: When we draw the scenario, we form a right triangle where: - The height of the pole \( h \) is one side (opposite side). - The length of the shadow \( s \) is the other side (adjacent side). - The angle of elevation \( \theta \) is the angle between the ground and the line of sight to the top of the pole. 3. **Using Trigonometric Ratios**: We can use the tangent function, which is defined as the ratio of the opposite side to the adjacent side: \[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{h}{s} \] Substituting the values we have: \[ \tan(\theta) = \frac{h}{3h} = \frac{1}{3} \] 4. **Finding the Angle**: Now we need to determine the angle \( \theta \) for which \( \tan(\theta) = \frac{1}{3} \). From trigonometric tables or a calculator, we find: \[ \theta = \tan^{-1}\left(\frac{1}{3}\right) \] This corresponds to an angle of \( 30^\circ \). 5. **Final Answer**: Therefore, the angle of elevation of the pole is: \[ \theta = 30^\circ \] ### Conclusion: The correct option is C. \( 30^\circ \).
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