If `! = div, # = +, " ^" = xx`, the calculate the value of `32!4 "^" 7 # 5`
A 58 B 61 C 64 D 55

Options

A. D
B. C
C. B
D. A

Answer

To solve the expression `32!4 "^" 7 # 5` with the given symbols, we need to replace the symbols with their respective operations:

- `!` means division (div)
- `#` means addition (+)
- `^` means multiplication (xx)

Now, let's rewrite the expression using these operations:

1. Replace `!` with division:
\[ 32!4 \text{ becomes } 32 \div 4 \]

2. Replace `^` with multiplication:
\[ 7 ^ 5 \text{ becomes } 7 \times 5 \]

3. Replace `#` with addition:
\[ 32!4 "^" 7 # 5 \text{ becomes } (32 \div 4) \times 7 + 5 \]

Now, we can calculate step by step:

### Step 1: Calculate \( 32 \div 4 \)
\[ 32 \div 4 = 8 \]

### Step 2: Multiply the result by 7
\[ 8 \times 7 = 56 \]

### Step 3: Add 5 to the result
\[ 56 + 5 = 61 \]

Thus, the final result of the expression `32!4 "^" 7 # 5` is \( 61 \).

### Conclusion
The correct answer is option B: 61.

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