If `Delta Ο= 52, square #=43` what is `# Delta square` ?
A 523
B. 243
C 432
D. 354

Options

A. C
B. B
C. A
D. D

Answer

To solve the question, we need to decode the symbols given in the problem statement.

1. **Identify the values of the symbols:**
- We are given that `Delta Ο = 52`. This means that the value of `Delta` (Δ) is 5 and the value of `Ο` is 2.
- We are also given that `square # = 43`. This means that the value of `square` (□) is 4 and the value of `#` is 3.

2. **Write down the values:**
- From `Delta Ο = 52`, we have:
- Δ = 5
- Ο = 2
- From `square # = 43`, we have:
- □ = 4
- # = 3

3. **Calculate the expression `# Delta square`:**
- We need to find the value of `# Δ □`.
- Substitute the values we found:
- # = 3
- Δ = 5
- □ = 4
- Therefore, `# Δ □ = 3 5 4`.

4. **Combine the values:**
- When we combine these values, we get the number 354.

5. **Final answer:**
- Thus, the value of `# Delta square` is **354**.

Now let's summarize the steps with hints: