The diagonal of a rhombus is 8m and 6m respectively. Find its area
A 48 sq.m
B 24 sq.m
C 12 sq.m
D. 96 sq.m

Options

A. A
B. B
C. C
D. D

Answer

To find the area of a rhombus given its diagonals, we can use the formula:

\[ \text{Area} = \frac{1}{2} \times d_1 \times d_2 \]

where \(d_1\) and \(d_2\) are the lengths of the diagonals.

### Step-by-Step Solution:

1. **Identify the lengths of the diagonals**:
- Given \(d_1 = 8 \, \text{m}\) and \(d_2 = 6 \, \text{m}\).

2. **Substitute the values into the area formula**:
\[ \text{Area} = \frac{1}{2} \times 8 \times 6 \]

3. **Calculate the product of the diagonals**:
\[ 8 \times 6 = 48 \]

4. **Multiply by \(\frac{1}{2}\)**:
\[ \text{Area} = \frac{1}{2} \times 48 = 24 \, \text{sq.m} \]

5. **Conclusion**:
The area of the rhombus is \(24 \, \text{sq.m}\).

### Final Answer:
The area of the rhombus is **24 sq.m** (Option B).

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