Home
Class 14
MATHS
A can do a work in 40 days, B can do the...

A can do a work in 40 days, B can do the same work in 60 days and C can do the same work in 80 days. They all together started the work and A left 11 days before also B left 8 days before the completion of whole task, find the number of days taken to complete the work.

A

A)13 days

B

B)26 days

C

C)39 days

D

D)52 days

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's break it down: ### Step 1: Determine the work done by A, B, and C in one day. - A can complete the work in 40 days, so A's work per day = \( \frac{1}{40} \) of the work. - B can complete the work in 60 days, so B's work per day = \( \frac{1}{60} \) of the work. - C can complete the work in 80 days, so C's work per day = \( \frac{1}{80} \) of the work. ### Step 2: Find the Least Common Multiple (LCM) to express total work in units. - The LCM of 40, 60, and 80 is 240. - Thus, we can assume the total work is 240 units. ### Step 3: Calculate the efficiency of A, B, and C in units. - A's efficiency = \( \frac{240}{40} = 6 \) units/day - B's efficiency = \( \frac{240}{60} = 4 \) units/day - C's efficiency = \( \frac{240}{80} = 3 \) units/day ### Step 4: Calculate the total efficiency when all three are working together. - Total efficiency = A's efficiency + B's efficiency + C's efficiency = \( 6 + 4 + 3 = 13 \) units/day. ### Step 5: Determine how many days A and B worked. - Let \( x \) be the total number of days taken to complete the work. - A left 11 days before completion, so A worked for \( x - 11 \) days. - B left 8 days before completion, so B worked for \( x - 8 \) days. - C worked for the entire duration, \( x \) days. ### Step 6: Set up the equation based on the work done. - Work done by A = \( 6(x - 11) \) - Work done by B = \( 4(x - 8) \) - Work done by C = \( 3x \) The total work done by A, B, and C should equal the total work (240 units): \[ 6(x - 11) + 4(x - 8) + 3x = 240 \] ### Step 7: Simplify the equation. Expanding the equation: \[ 6x - 66 + 4x - 32 + 3x = 240 \] Combine like terms: \[ (6x + 4x + 3x) - 98 = 240 \] \[ 13x - 98 = 240 \] ### Step 8: Solve for \( x \). Add 98 to both sides: \[ 13x = 240 + 98 \] \[ 13x = 338 \] Now divide by 13: \[ x = \frac{338}{13} = 26 \] ### Conclusion: The total number of days taken to complete the work is **26 days**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

A and B can do a work in 12 days, Band C can do the same work in 15 days, C and A can do the same work in 20 days. The time taken by A, B and C to do the same work is

A,B and C can do a work in 20,45 and 120 days respectively.They started the work. A left 10 days before and B left 5 days before the completion of work. In how many days is the total work completed ?

A,B and C can do a work in 20,45 and 120 days respectively.They started the work. A left 10 days before and B left 5 days before the completion of work. In how many days is the total work completed ?

If A can do a piece of work in 4 days, B can do the same work in 8 days and C can do the same work in 12 days , then working together , how many days will they take to complete the work ?

If P can do a work in 6 days and Q Can do the same work in 8 days. R can do the same work in 12 days. If they are woeking together then the work will be completed in how many days?

A, B and C can do a work in 12, 15 and 18 days respectively. They started the work together but A left after 2 days and B left the work 3 days before the competition of work. Find the number of days it took them to complete the work.

A can do a work in 4 days while B can do that same work in 6 days. If they worked together, then that work would be completed in