The sum of three consecutive numbers is 126 . Find the highest number .
A.41
B. 42
C. 43
D. 44

Options

A. D
B. B
C. A
D. C

Answer

To solve the problem of finding the highest of three consecutive numbers whose sum is 126, we can follow these steps:

### Step 1: Define the Consecutive Numbers
Let the three consecutive numbers be:
- First number: \( x - 1 \)
- Second number: \( x \)
- Third number: \( x + 1 \)

### Step 2: Set Up the Equation
According to the problem, the sum of these three consecutive numbers is 126. Therefore, we can write the equation:
\[ (x - 1) + x + (x + 1) = 126 \]

### Step 3: Simplify the Equation
Now, simplify the left side of the equation:
\[ x - 1 + x + x + 1 = 126 \]
This simplifies to:
\[ 3x = 126 \]

### Step 4: Solve for \( x \)
To find \( x \), divide both sides of the equation by 3:
\[ x = \frac{126}{3} = 42 \]

### Step 5: Find the Highest Number
The highest of the three consecutive numbers is:
\[ x + 1 = 42 + 1 = 43 \]

### Conclusion
Thus, the highest number is **43**.