Home
Class 14
MATHS
Side of a hexagon is 4cm . Side of a squ...

Side of a hexagon is 4cm . Side of a square is `4sqrt(2)` cm . What is the ratio of their areas ?

A

`3sqrt(3) : 2`

B

`3sqrt(3) : 4`

C

`sqrt(3)//2 : 1`

D

`2sqrt(3) : 1`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of the areas of a hexagon and a square, we will follow these steps: ### Step 1: Calculate the area of the hexagon The formula for the area of a regular hexagon with side length \( a \) is given by: \[ \text{Area} = \frac{3\sqrt{3}}{2} a^2 \] Given that the side of the hexagon is \( 4 \, \text{cm} \): \[ \text{Area of hexagon} = \frac{3\sqrt{3}}{2} (4)^2 = \frac{3\sqrt{3}}{2} \times 16 = 24\sqrt{3} \, \text{cm}^2 \] ### Step 2: Calculate the area of the square The formula for the area of a square with side length \( a \) is: \[ \text{Area} = a^2 \] Given that the side of the square is \( 4\sqrt{2} \, \text{cm} \): \[ \text{Area of square} = (4\sqrt{2})^2 = 16 \times 2 = 32 \, \text{cm}^2 \] ### Step 3: Find the ratio of the areas Now, we need to find the ratio of the area of the hexagon to the area of the square: \[ \text{Ratio} = \frac{\text{Area of hexagon}}{\text{Area of square}} = \frac{24\sqrt{3}}{32} \] ### Step 4: Simplify the ratio To simplify the ratio, we can divide both the numerator and the denominator by 8: \[ \frac{24\sqrt{3}}{32} = \frac{3\sqrt{3}}{4} \] ### Final Answer Thus, the ratio of the areas of the hexagon to the square is: \[ \text{Ratio} = 3\sqrt{3} : 4 \] ---
Promotional Banner

Similar Questions

Explore conceptually related problems

The side of a hexagon is 4 cm. The side of a square is 4 sqrt2 cm. Find the ratio of their areas. किसी षट्भुज की भुजा 4 cm है | किसी वर्ग की भुजा 4 sqrt2 cm है |उनके क्षेत्रफल का अनुपात कितना है?

The side of a square is 4 cm. What will be its area?

The length of the diagonal of a square and that of the side of another square are both 10 cm. What is the ratio of the area of the first square to that of the second ?

The side of an equilateral triangle is equal to the diagonal of the square. If the side of the square is 12 cm, then what is the area of the equilateral triangle?

The length of each side of a rhombus is equal to the length of the side of a square whose diagonal is 40sqrt(2) cm. If the length of the diagonals of the rhombus are in the ratio 3:4. then its area (in cm^(2) ) is

If one side of a square is 4 cm, then what will be its area and perimeter?