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Two trains cross each other in 12 second...

Two trains cross each other in 12 seconds , when they travel in opposite directions and they take 60 seconds when they travel in the same direction. The possible speeds of the trains, (inm/sec), can be:

A

15, 45

B

18, 40

C

15, 30

D

20, 30

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of two trains crossing each other, we need to analyze the information given about their crossing times in both opposite and same directions. ### Step-by-Step Solution: 1. **Understanding the Problem**: - Let the speed of the first train be \( S_1 \) m/s. - Let the speed of the second train be \( S_2 \) m/s. - The time taken to cross each other when traveling in opposite directions is 12 seconds. - The time taken to cross each other when traveling in the same direction is 60 seconds. 2. **Setting Up the Equations**: - When the trains cross each other in opposite directions, the distance covered is the sum of their lengths, which can be expressed as: \[ \text{Distance} = (S_1 + S_2) \times 12 \] - When the trains cross each other in the same direction, the distance covered is the difference of their lengths: \[ \text{Distance} = (S_1 - S_2) \times 60 \] 3. **Equating the Distances**: - Since the distance is the same in both cases, we can set the two equations equal to each other: \[ (S_1 + S_2) \times 12 = (S_1 - S_2) \times 60 \] 4. **Expanding and Rearranging**: - Expanding both sides gives: \[ 12S_1 + 12S_2 = 60S_1 - 60S_2 \] - Rearranging the equation: \[ 12S_1 + 12S_2 + 60S_2 = 60S_1 \] \[ 12S_1 + 72S_2 = 60S_1 \] - Bringing all terms involving \( S_1 \) to one side: \[ 72S_2 = 60S_1 - 12S_1 \] \[ 72S_2 = 48S_1 \] 5. **Finding the Ratio of Speeds**: - Dividing both sides by 12 gives: \[ 6S_2 = 4S_1 \] - Rearranging gives the ratio of the speeds: \[ \frac{S_1}{S_2} = \frac{6}{4} = \frac{3}{2} \] 6. **Identifying Possible Speeds**: - This ratio indicates that for every 3 units of speed of the first train, the second train has 2 units of speed. - If we assume \( S_2 = 2x \) and \( S_1 = 3x \), we can substitute different values for \( x \) to find possible speeds. 7. **Conclusion**: - The possible speeds of the trains can be expressed in the ratio \( 3:2 \). - Therefore, if we check the options provided in the question, we can find which pair of speeds maintains this ratio.
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