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The time required for Rs 1,000 to amoun...

The time required for Rs 1,000 to amount to 1,331 at interest of 10% per annum, compounded annually, is

A

2 years

B

2 years, 6 months

C

3 years

D

3 years, 6 months

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the time required for Rs. 1,000 to amount to Rs. 1,331 at an interest rate of 10% per annum, compounded annually, we can use the formula for compound interest. ### Step-by-Step Solution: 1. **Understand the Compound Interest Formula**: The formula for compound interest is given by: \[ A = P \left(1 + \frac{r}{100}\right)^t \] where: - \( A \) = final amount - \( P \) = principal amount (initial investment) - \( r \) = rate of interest per annum - \( t \) = time in years 2. **Identify the Given Values**: From the problem, we have: - \( A = 1331 \) - \( P = 1000 \) - \( r = 10\% \) 3. **Substitute the Values into the Formula**: Plugging the values into the compound interest formula: \[ 1331 = 1000 \left(1 + \frac{10}{100}\right)^t \] Simplifying the expression inside the parentheses: \[ 1331 = 1000 \left(1 + 0.1\right)^t \] \[ 1331 = 1000 \left(1.1\right)^t \] 4. **Isolate the Exponential Term**: To isolate \( (1.1)^t \), divide both sides by 1000: \[ \frac{1331}{1000} = (1.1)^t \] \[ 1.331 = (1.1)^t \] 5. **Recognize the Exponential Relationship**: Notice that \( 1.331 \) can be expressed as \( (1.1)^3 \): \[ 1.331 = (1.1)^3 \] Therefore, we can equate the exponents since the bases are the same: \[ t = 3 \] 6. **Conclusion**: The time required for Rs. 1,000 to amount to Rs. 1,331 at an interest rate of 10% per annum, compounded annually, is **3 years**.
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Knowledge Check

  • Find the amount of Rs 1000 after 4 years at the rate of 10% per annum compounded annually.

    A
    1464.1
    B
    1444.2
    C
    1452.2
    D
    1425.2
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    A
    2 years
    B
    3 years
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    5 years
    D
    4 years
  • In how many years will Rs.1,800 amount to Rs.2,178 at 10% per annum when compounded annually?

    A
    2.5
    B
    3.5
    C
    2
    D
    3
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