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The lengths of two diagonals of a rhombu...

The lengths of two diagonals of a rhombus are 10 cm and 24 cm. What is the area (in `cm^(2)`) of the rhombus?

A

60

B

90

C

120

D

240

Text Solution

AI Generated Solution

The correct Answer is:
To find the area of a rhombus given the lengths of its diagonals, we can use the formula: \[ \text{Area} = \frac{1}{2} \times d_1 \times d_2 \] where \(d_1\) and \(d_2\) are the lengths of the diagonals. ### Step-by-step Solution: 1. **Identify the lengths of the diagonals**: - Given \(d_1 = 10 \, \text{cm}\) and \(d_2 = 24 \, \text{cm}\). 2. **Substitute the values into the area formula**: \[ \text{Area} = \frac{1}{2} \times 10 \times 24 \] 3. **Calculate the product of the diagonals**: \[ 10 \times 24 = 240 \] 4. **Multiply by \(\frac{1}{2}\)**: \[ \text{Area} = \frac{1}{2} \times 240 = 120 \, \text{cm}^2 \] 5. **Conclusion**: The area of the rhombus is \(120 \, \text{cm}^2\).
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