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A person goes from point A to B and come...

A person goes from point A to B and comes back. His average speed for the whole journey is 65 km/hr. If his speed while coming back from B to A is 40 km/hr, then what will be the speed of the person (in km/hr) while going from A to B?

A

90

B

`173.33`

C

104

D

112

Text Solution

AI Generated Solution

The correct Answer is:
To find the speed of the person while going from point A to point B, we can use the concept of average speed and the relationship between distance, speed, and time. ### Step-by-Step Solution: 1. **Define Variables**: Let the distance from A to B be \( x \) km. The speed from A to B is \( S \) km/hr, and the speed from B to A is given as 40 km/hr. 2. **Calculate Total Distance**: The total distance for the round trip (A to B and back to A) is: \[ \text{Total Distance} = x + x = 2x \text{ km} \] 3. **Calculate Time Taken for Each Leg of the Journey**: - Time taken to go from A to B: \[ \text{Time}_{AB} = \frac{x}{S} \text{ hours} \] - Time taken to return from B to A: \[ \text{Time}_{BA} = \frac{x}{40} \text{ hours} \] 4. **Calculate Total Time**: The total time for the journey is: \[ \text{Total Time} = \text{Time}_{AB} + \text{Time}_{BA} = \frac{x}{S} + \frac{x}{40} \] 5. **Use Average Speed Formula**: The average speed for the whole journey is given as 65 km/hr. The formula for average speed is: \[ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \] Substituting the known values: \[ 65 = \frac{2x}{\frac{x}{S} + \frac{x}{40}} \] 6. **Simplify the Equation**: To simplify, multiply both sides by the total time: \[ 65 \left( \frac{x}{S} + \frac{x}{40} \right) = 2x \] Dividing through by \( x \) (assuming \( x \neq 0 \)): \[ 65 \left( \frac{1}{S} + \frac{1}{40} \right) = 2 \] 7. **Rearranging the Equation**: \[ \frac{1}{S} + \frac{1}{40} = \frac{2}{65} \] Now, isolate \( \frac{1}{S} \): \[ \frac{1}{S} = \frac{2}{65} - \frac{1}{40} \] 8. **Finding a Common Denominator**: The least common multiple of 65 and 40 is 520. Convert each fraction: \[ \frac{2}{65} = \frac{16}{520}, \quad \frac{1}{40} = \frac{13}{520} \] Thus, \[ \frac{1}{S} = \frac{16}{520} - \frac{13}{520} = \frac{3}{520} \] 9. **Reciprocate to Find S**: \[ S = \frac{520}{3} \approx 173.33 \text{ km/hr} \] ### Final Answer: The speed of the person while going from A to B is approximately **173.33 km/hr**.
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