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Ankit is 5 times as heavy as Suraj. Sura...

Ankit is 5 times as heavy as Suraj. Suraj is one third the weight of Imran. Imran is 4/3 times as heavy as Shrey. Shrey is half the weight of Gagan. Who is the lightest?

A

Imran

B

Shrey

C

Suraj

D

Suraj or Shrey

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will define the weights of each person using variables and then relate them according to the information given in the question. ### Step 1: Define Suraj's Weight Let the weight of Suraj be \( X \). ### Step 2: Calculate Ankit's Weight According to the problem, Ankit is 5 times as heavy as Suraj. Therefore, Ankit's weight will be: \[ \text{Weight of Ankit} = 5X \] ### Step 3: Calculate Imran's Weight Suraj is one third the weight of Imran. This means: \[ \text{Weight of Imran} = 3 \times \text{Weight of Suraj} = 3X \] ### Step 4: Calculate Shrey's Weight Imran is \( \frac{4}{3} \) times as heavy as Shrey. Therefore, we can express Shrey's weight as: \[ \text{Weight of Shrey} = \frac{3}{4} \times \text{Weight of Imran} = \frac{3}{4} \times 3X = \frac{9X}{4} \] ### Step 5: Calculate Gagan's Weight Shrey is half the weight of Gagan. Thus, we can express Gagan's weight as: \[ \text{Weight of Gagan} = 2 \times \text{Weight of Shrey} = 2 \times \frac{9X}{4} = \frac{18X}{4} = \frac{9X}{2} \] ### Step 6: Compare All Weights Now we have the weights expressed in terms of \( X \): - Suraj: \( X \) - Ankit: \( 5X \) - Imran: \( 3X \) - Shrey: \( \frac{9X}{4} \) - Gagan: \( \frac{9X}{2} \) ### Step 7: Determine the Lightest To find the lightest person, we compare the coefficients: - \( X \) (Suraj) - \( 5X \) (Ankit) - \( 3X \) (Imran) - \( \frac{9X}{4} \) (Shrey) - \( \frac{9X}{2} \) (Gagan) Among these, \( X \) (Suraj) is the smallest value. ### Conclusion Thus, the lightest person is **Suraj**.
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