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Two numbers are 25% and 15% less than th...

Two numbers are `25% and 15%` less than the third number respectively. First number is what percent less than the second number?

A

`11.76`

B

`13.5`

C

`17.8`

D

`20.4`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these calculations: 1. **Assume the third number**: Let's denote the third number as \( x \). 2. **Calculate the first number**: The first number is 25% less than the third number. Therefore, the first number can be expressed as: \[ \text{First Number} = x - 0.25x = 0.75x \] 3. **Calculate the second number**: The second number is 15% less than the third number. Thus, the second number can be expressed as: \[ \text{Second Number} = x - 0.15x = 0.85x \] 4. **Find the difference between the first and second numbers**: We need to find how much less the first number is than the second number. The difference is: \[ \text{Difference} = \text{Second Number} - \text{First Number} = 0.85x - 0.75x = 0.10x \] 5. **Calculate the percentage difference**: To find out what percent the first number is less than the second number, we use the formula: \[ \text{Percentage} = \left( \frac{\text{Difference}}{\text{Second Number}} \right) \times 100 \] Substituting the values we have: \[ \text{Percentage} = \left( \frac{0.10x}{0.85x} \right) \times 100 \] 6. **Simplify the expression**: The \( x \) cancels out: \[ \text{Percentage} = \left( \frac{0.10}{0.85} \right) \times 100 \] 7. **Calculate the final value**: \[ \text{Percentage} = \left( \frac{10}{85} \right) \times 100 = \frac{1000}{85} \approx 11.76\% \] Thus, the first number is approximately **11.76% less than the second number**.
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