Home
Class 12
MATHS
The point at which the normal to the cur...

The point at which the normal to the curve `y = x+(1)/(x), x gt 0` is perpendicular to the line 3x – 4y – 7 = 0 is:

A

(2, 5/2)

B

`(pm 2, 5//2)`

C

`(-1//2, 5//2)`

D

`(1//2, 5//2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER 2022

    CBSE MODEL PAPER|Exercise SECTION – B |20 Videos

  • SAMPLE PAPER 2022

    CBSE MODEL PAPER|Exercise SECTION – C |10 Videos

  • SAMPLE QUESTION PAPER ( MATHEMATICS )

    CBSE MODEL PAPER|Exercise QUESTION|60 Videos

  • SAMPLE PAPER 2022 TERM II

    CBSE MODEL PAPER|Exercise SECTION C|5 Videos

Similar Questions

Explore conceptually related problems

Find the equation of the normal to the curve y= x+1/x ,x gt 0 perpendicular to the line 3x - 4y =7 .

Find the equation of normal to the curve y=sqrt(x-3) which is perpendicular to the line 6x+ 3y-4=0

The slope of normal to the curve y = x + (1)/(x) , x gt 0 at   x =2 is :

The point on the curve y= sqrt(x-1) where the tangent is perpendicular to the line 2x+y-5=0 is

The point on the curve y=sqrt(x-1) , where the tangent is perpendicular to the line 2x+y-5=0 is

Point on the curve y=x^(4)+5 , the normal at which is prependicular to the line 4x-y-1=0 is

Find the equations of the normal to the curve y=4x^(3)-3x+5 , which are perpendicular to the line : 9x-y+5=0 .

Point on the curve x^(2)=4y^(3) , the tangent at which is prependicular to the line 3x+y=1 is

The equation of normal to the curve y=6-x^(2), where the normal is parallel to the line x-4y+3=0 is

The point on the curve y=3x^(2)+2x+5 at which the tangent is perpendicular to the line x+2y+3=0