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Given that A=[(alpha, beta),(gamma, alph...

Given that `A=[(alpha, beta),(gamma, alpha)] and A^(2) =3I`, then :

A

`1+ alpha^(2) + beta gamma =0`

B

`1-alpha^(2)-beta gamma=0`

C

`3- alpha^(2)-beta gamma =0`

D

`3+ alpha^(2)+ beta gamma=0`

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