`mu_0 epsilon_0` का विमीय सूत्र है

Options

A. `M^0 L^(-2) T^(2)`
B. `M^(0) L^(2) T^(-2)`
C. `M^(0)L^(1)T^(-1)`
D. `M^(0)L^(-1)T^(1)`

Answer

A

Explanation

`C = 1/(sqrt(mu_0 epsilon_0)) implies mu_0 epsilon_0 = 1/(C^2)`
`C to M^(0)L^(1) T^(-1)`
`implies 1/(C^2) to M^(0)L^(-2) T^(2)`