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Find the enthalpy of formation of hydrog...

Find the enthalpy of formation of hydrogen flouride on the basis of following data:
Bond energy of `H-H` bond `=434 kJ mol^(-1)`
Bond energy of `F-F` bond `=158 kJ mol^(-1)`
Bond enegry of `H -F` bond `=565 kJ mol^(-1)`

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Calculate the enthalpy of formation of ammonia from the following bond enegry data: (N-H) bond = 389 kJ mol^(-1), (H-H) bond = 435 kJ mol^(-1) , and (N-=N)bond = 945.36kJ mol^(-1) .

Calculate the enthalpy of formation of ammonia from the following bond energy data: (N-H) bond = 389 kJ mol^(-1), (H-H) bond = 435 kJ mol^(-1) , and (N-=N)bond = 945.36kJ mol^(-1) .

Using the bond enthalpy data given below, calculate the enthalpy of formation of acetone (g). Bond enegry C-H = 413.4 kJ mol^(-1) , Bond enegry C-C = 347.0 kJ mol^(-1) , Bond enegry C=O = 728.0 kJ mol^(-1) , Bond enegry O=O = 495.0 kJ mol^(-1) , Bond enegry H-H = 435.8 kJ mol^(-1) , Delta_("sub")H^(Theta)C(s) = 718.4 kJ mol^(-1)

Using the bond enthalpy data given below, calculate the enthalpy of formation of acetone (g). Bond enegry C-H = 413.4 kJ mol^(-1) , Bond enegry C-C = 347.0 kJ mol^(-1) , Bond enegry C=O = 728.0 kJ mol^(-1) , Bond enegry O=O = 495.0 kJ mol^(-1) , Bond enegry H-H = 435.8 kJ mol^(-1) , Delta_("sub")H^(Theta)C(s) = 718.4 kJ mol^(-1)

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