निम्नलिखित सेल के सेल विभव की गणना कीजिए।
`Pt(s)|H_(2)(g)(0.1 बार)|BOH(0.1M)||HA(0.1M)|H_(2)(g)(1 बार )|Pt`
दिया गया है
`K_(a)(HA)=10^(-7),K_(b)(BOH)=10^(-5)`

Options

A. 0.39V
B. 0.36V
C. 0.93V
D. 0.63V

Answer

A

Explanation

`E_("सेल")=0.059/2"log"([H^(+)]_("कैथोड")^(2)xx[P_(H_(2))]_("ऐनोड"))/([H^(+)]_("ऐनोड")^(2)xx[P_(H_(2))]_("कैथोड"))`
`[OH^(-)]=sqrt(CK_(b))=sqrt(0.1xx10^(-5))`
`=10^(-3)M`
`[H^(+)]_("ऐनोड")=10^(-14))/(10^(-3))=10^(-11)M`
`[H_(+)]_("कैथोड")=sqrt(CK_(a))=sqrt(0.1xx10^(-7))`
`=10^(-4)M`
इसलिए `E_("cell")=0.059/2"log"((10^(-4))^(2)xx0.1)/((10^(-11))^(2)xx1)`
`=0.39V`