Home
Class 12
CHEMISTRY
निम्नलिखित अभिक्रिया के लिए Ag((aq))^(...

निम्नलिखित अभिक्रिया के लिए
`Ag_((aq))^(+)+Cl_((aq))^(-)toAgCl_((s))`
दिया गया है `DeltaG_(f)^(@),AgCl=-112.44` kJ/mol
`DeltaG_(f)^(@)Cl^(-)=-130`kJ/mol, `DeltaG_(f)^(@)Ag^(+)=75` kJ/mol
AgCl का `K_(sp)nxx10^(-10)` है। n का मान क्या है? (निकटतम पूर्णांक में अपन उत्तर दीजिए)

Text Solution

Verified by Experts

The correct Answer is:
A
`Ag_((aq))^(+)+Cl_((aq))^(-)toagCl_((s))`
`DeltaG_(f)^(@),AgCl=-112.44` kj/mol `DeltaG_(f)^(@)Cl^(-)`
`=-130` kJ/mol, `DeltaG_(f)^(@)Ag^(+)=75` kJ/mol
`Delta_("अभिक्रिया")^(@)=DeltaG_(f)^(@)`
`Agcl-DeltaG_(f)^(@)Ag^(+)+DeltaG_(f)^(@)Cl^(-)`
`=-112.44kj[75kJ-130kJ]`
`=-57.44kJ`
`2.303RT log K_(sp)=DeltaG_("अभिक्रिया")^(@)`
`logK_(sp)=57440/(2.303xx8.314xx298)~=10`
`K_(sp)=1xx10^(-10)`
अतः n=1
Promotional Banner

Similar Questions

Explore conceptually related problems

For the following reaction Ag_((aq))^(+)+Cl_((aq))^(-)rarrAgCl_((s)) Given : DeltaG_(f)^(@), AgCl=-"112.44 kJ/mol," DeltaG_(f)^(@) Cl^(-)=-"130 kJ/mol", DeltaG_(f)^(@)Ag^(+)="75 kJ/mol" Report your answer by rounding it upto nearest whole number. The K_(sp) of AgCl is nxx10^(-10) . The value of 'n'' is .

For the following cell reaction {:(Ag|Ag^(+)|AgCl|Cl^(-)|Cl_(2),Pt),(DeltaG_(f)^(@)(AgCl)=-109kJ/mol,),(DeltaG_(f)^(@)(Cl^(-))=-129kJ/mol and),(DeltaG_(f)^(@)(Ag^(+))=78KJ/mol.E^(@)):} of the cell is

Calculate Delta_(r)G^(c-) of the reaction : Ag^(o+)(aq)+Cl^(c-)(aq) rarr AgCl(s) Given :Delta_(f)G^(c-)._(AgCl)=-109kJ mol ^(-1) Delta_(f)G^(c-)_((Cl^(c-)))=-129k J mol ^(-1) Delta_(f)G^(c-)._((Ag^(o+)))=-77 kJ mol ^(-1)

Calculate the standard enthalpy of solution of AgCl(s) in water DeltaH_(f)^(0)(AgCl,s)= -127.07kJ mol^(-1), Delta H_(f)^(0)(Ag^(+),aq)=105.58 kJ mol^(-1),DeltaH_(f)^(0)(Cl^(-),aq)= -167.35 kJ mol^(-1)

Calculate the pH at which the following reaction will be at equilibrium in basic medium : A_(2)(s) hArr A^(-)(aq) +AO_(3)^(-) (aq) When the equilibrium concentration at 300 K are: [A^(-)] = 0.1M, [AO_(3)^(-)] = 0.1M Given: DeltaG_(f)^(@) of OH^(-)(aq) =- 150 kJ//"mole" , DeltaG_(f)^(@) "of" H_(2)O(l) =- 233 kJ//"mole" DeltaG_(f)^(@) "of" A^(-)(aq) =- 50 kJ//"mole" , DeltaG_(f)^(@) "of" AO_(3)^(-) (aq) =- 123.5 kJ//"mole" , R = (25)/(3) J "mole"^(-1) K^(-1), log_(e) 10 = 2.3