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अभिक्रिया के लिए साम्यावस्था स्थिरांक की...

अभिक्रिया के लिए साम्यावस्था स्थिरांक की गणना कीजिए (`10^(12)` में)
`Fe^(2+) + Ce^(4+) hArr Fe^(3+) +Ce^(3+)`
दिया गया है,
`E^(@) (Ce^(4+)//Ce^(3+)) =1.44V, E^(@) (Fe^(3+)//Fe^(2+))=0.68V`
`{(RT)/(F)= .0591}`

Text Solution

Verified by Experts

`Fe^(2+) +Ce^(4+) hArr Fe^(3+) +Ce^(3+)`
`E^(@) =E^(@) (Ce^(4+)//Ce^(3+)) -E^(@) (Fe^(3+)//Fe^(2+))`
`=1.44-0.68=1.76V`
`:. E^(@)=0.059logK`
`rArr logK=(E^(@))/(0.0592)`
`=(0.76)/(0.059)=12.85`
`rArr K=7.07xx10^(12)`
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