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दिया गया है: C ("ग्रेफाइट") + O2 (g) t...

दिया गया है: _
`C ("ग्रेफाइट") + O_2 (g) to CO_2 (g) , Delta_rH^@= -393.5 kJmol^(-1)`
`H_2(g) + 1/2 O_2 (g) to H_2O (I), Delta_rH^@ = -285.8 kJmol^(-1)`
`CO_2 (g) + 2H_2O (I) to CH_4 (g) + 2O_2 (g), Delta_rH^@ = +890.3 kJmol^(-1)`
उपरोक्त ऊष्मरासायनिक समीकरणों के आधार पर,
K पर, निम्नलिखित अभिक्रिया के लिए `Delta_r H^@` का मान होगा:
`C "(ग्रेफाइट)" + 2H_2 (g)to CH_4 (g)`

A

`+144.0 kJmol^(-1)`

B

`-74.8 kJmol^(-1)`

C

`-144.0 kJmol^(-1)`

D

`+74.8 kJmol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
अभिक्रिया के लिए
`CO_2(g)+2H_2O(I) to CH_4(g)+2O_2(g)`
`Delta_rH^@ = Sigma(Delta_fH^@)_("उत्पाद") -Sigma(Delta_fH^@)_("अभिकारक")`
`=[(Delta_rH^@(CH_4)+2xx0)+890.3= [Delta_fH^@(CH_4)]-[-393.5+2xx(-285.8)]`
`CH_4 (g) " का " Delta_fH^@ = -74.8 KJ//mol`
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Calculate enthalpy of formation of methane (CH_4) from the following data : (i) C(s) + O_(2)(g) to CO_(2) (g) , Delta_rH^(@) = -393.5 KJ mol^(-1) (ii) H_2(g) + 1/2 O_(2)(g) to H_(2)O(l) , Deta_r H^(@) = -285.5 kJ mol^(-1) (iii) CH_(4)(g) + 2O_(2)(g) to CO_(2)(g) + 2H_(2)O(l), Delta_(r)H^(@) = -890.3 kJ mol^(-1) .

Calculate the enthalpy of formation of methane from the following data : C(s) + O_(2)(g) to CO_(2)(g) Delta_(r)H^(@) = -393.5 kJ 2H_(2)(g) + O_(2)(g) to 2H_(2)O(l) Delta_(r)H^(@) = -571.8 kJ CH_(4)(g) + 2O_(2)(g) to CO_(2)(g) + 2H_(2)O(l) Delta_(r)H^(@) = -890.3 kJ