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300K पर अभिक्रिया A(1) to 2B(g) के लिए D...

300K पर अभिक्रिया `A(1) to 2B(g)` के लिए `DeltaU = 2.1k Cal, DeltaS = 20 CalK^(-1)` है, इसलिए `DeltaG` का मान kcal में क्या होगा ?

A

2.7

B

`- 2.7 `

C

`5.4 `

D

`1.35 `

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaH = DeltaU + Deltang RT`
` 2.1 xx 10^3 + 2(2)(300) = 3300 Cal`
`DeltaG = DeltaH - T DeltaS`
`= 3300 - 300 (20) = -2700 Cal`
`= -2.7 K Cal`.
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