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45 nm तरंगदैर्ध्य के प्रकाश की जूल में ऊ...

`45 nm` तरंगदैर्ध्य के प्रकाश की जूल में ऊर्जा परिकलित कीजिए। (प्लांक स्थिरांक, `h = 6.63 xx 10^(-34) Js` , प्रकाश की चाल, `c=3xx 10^8 ms^(-1))`

A

`6.67xx10^(11)`

B

`4.42xx10^(-15)`

C

`6.67xx10^(15)`

D

`4.42xx10^(-18)`

Text Solution

Verified by Experts

The correct Answer is:
D
`E = (hc)/lambda = (6.63xx10^(-34)xx3xx10^8)/(45xx10^(-9)`
`E = 4.42xx10^(-18) J`
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