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25°C पर, सेल Pt(s)|H(3)(1.0 "atm")|H^(+)...

25°C पर, सेल `Pt(s)|H_(3)(1.0 "atm")|H^(+)(aq)| Ag^(+)(1.0 M) |Ag(s)` मापित वोल्टेज, 1.02 V है। दिया गया `E("सेल")^(@) .0.80 V` है, विलयन के pH की गणना कीजिए।

A

1.86

B

1.69

C

3.73

D

7.43

Text Solution

Verified by Experts

The correct Answer is:
C
`E_("cell") = E_("cell")^(@) -0.059/n log ([H^(+)]^(2))/([Ag^(+)]^(2))`
`=E_("cell")^(@) -(0.059 xx 2)/2 log ([H^(+)])/([Ag^(+)])`
`E_("cell")^(@) -0.059 (-log [H^(+)])^(1)`
`=E_("cell")^(@) + 0.059 pH`
इसलिए, `pH = (E_("cell") - E_("cell")^(@))/0.059 = (1.02 -0.80)/0.059 = 3.73`
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