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If x+y+z=1,xy+yz+zx=-26 and x^3+y^3+z^3...

If x+y+z=1,xy+yz+zx=-26` and ``x^3+y^3+z^3=151`, then what will be the value of 3xyz ?

A

228

B

`-30`

C

`72`

D

32

Text Solution

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The correct Answer is:
A
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