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If x + y + z = 17, xyz= 171 and xy + zx ...

If x + y + z = 17, xyz= 171 and xy + zx + yx = 111, then the value of `root (3)(x^3+y^3+z^3+xyz)` is :

A

0

B

-4

C

4

D

-64

Text Solution

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The correct Answer is:
B
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