Energy of SHM#!#Time Period of SHM

Maximum kinetic energy of a particle of mass 1 kg in SHM is 8 J. Time period of SHM is 4 s. Maximum potential energy during the motion is 10 J. Then

A particle performing SHM takes time equal to T (time period of SHM ) in consecutive appearances at a perticular point. This point is :

If displacement x and velocity v related as 4v^(2) = 25 - x^(2)m in a SHM Then time period of given SHM is (consider SI unit)

Assertion : If amplitude of SHM is increased , time period of SHM will increase. Reason: If amplitude is increased, body have to travel more distance in one complete oscillation.

Find the time period of SHM of the block of mass M

The kinetic energy of SHM is 1/n time its potential energy. If the amplitude of the SHM be A, then what is the displacement of the particle ?

Statement-1: kinetic energy of SHM at mean position is equal to potential energy at ends for a particle moving in SHM. Statement-2: Total energy in SHM is conserved.

Which of following in an equation of SHM with time period pi/omega ?