EMF #!#Internal Resistance#!#Terminal Voltage

Two cells of emf E_(1) and E_(2) are joined in opposition (such that E_(1) gt E_(2) ) . If r_(1) be the internal resistances and R be the external resistance, then the terminal potential difference is

A storage battery has e.m.f. 15 volts and internal resistance 0.05 ohm . Its terminal voltage when it is delivering 10 ampere is

A battery of emf 15 V and internal resistance of 4Omega is connected to a resistor. If the current in the circuit is 2A and the circuit is closed. Resistance of the resistor and terminal voltage of the battery will be

Terminal voltage of cell (emf = 3V & internal resistance = r) is equal to 2.5V and heat loss in R is given by 0.5Watt find power loss in internal resistance

.A cell of emf E and internal resistance r is connected across a variable resistor. Plot a graph showing variation of terminal voltage V of cell versus the current.

A cell of emf E and internal resistance r is connected in series with an external resistance nr. Than what will be the ratio of the terminal potential difference to emf, if n=9.

A cell of e.m.f (E) and internal resistance (r) is connected in series with an external resistance (nr.) then the ratio of the terminal p.d. to E.M.F is