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Let the equation x^(2)+y^(2)+px+(1-p)y=0...

Let the equation `x^(2)+y^(2)+px+(1-p)y=0` represent circles of varying radius `r in (0,5]`. Then the number of elements in the set `S={q : q =p^(2)` and q is an integer } is __________.

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Knowledge Check

  • Value of p, of which are the equation x^2+y^2-2px+4y-12=0 represent a circle of radius 5 units is

    A
    3
    B
    -3
    C
    BPTH (a)&(b)
    D
    neither (a) nor (b)

  • If the equation , px^(2) + (2-q) xy + 3y^(2) - 6qx + 30y +6y = 0 represents a circle , then : (p,q) -=

    A
    `(3,1)`
    B
    `(2,2)`
    C
    `(3,2)`
    D
    `(3,4)`

  • If x^2+y^2+px+y(1-p)=0 is the equation of circle r in (0,5] , q=p^2 then number of integral value of (p,q) satisfy is

    A
    16
    B
    14
    C
    19
    D
    21

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