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A block of mass m slides on the wooden w...

A block of mass m slides on the wooden wedge, which in turn slides backward on the horizontal surface. The acceleration of the block with respect to the wedge is :
Given `m = 8 kg, M = 16 mg`
Assume all the surfaces shown in the figure to be frictionless.

A

`3/5 g`

B

`6/5 g`

C

`4/3 g`

D

`2/3g`

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Knowledge Check

  • The minimum value of acceleration of wedge for which the block start sliding on the wedge, is:

    A
    `g((costheta+musintheta)/(sintheta-mucostheta))`
    B
    `g((sintheta+mucostheta)/(costheta-musintheta))`
    C
    `g((sintheta-mucostheta)/(sintheta+mucostheta))`
    D
    `g((costheta-musintheta)/(sintheta+mucostheta))`

  • A block of mass m rests on a stationary wedge of mass M. The wedge can slide freely on a smooth horizontal surface as shown in figure. If the block starts from rest

    A
    (a) the position of the centre of mass of the system will change
    B
    (b) the position of centre of mass of the system will change along the vertical but not along the horizontal
    C
    (c) the total energy of the system will remain constant
    D
    (d) All of the above

  • All the surfaces are smooth as shown in figure. The acceleration of mass m relative to wedge is :

    A
    g sin `theta`
    B
    g sin `theta` + a cos `theta`
    C
    g sin `theta` - a cos `theta`
    D
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