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If the velocity of a body related to displacement x is given by `v=sqrt(5000+24x)` m/s, then the acceleration of the body is _______`m//s^(2)`.

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Knowledge Check

  • The velocity v and displacement r of a body are related as v^(2) =kr , where k is a constant. The acceleration of the body is

    A
    `sqrt(kr)`
    B
    `kr^(3//2)`
    C
    k/2
    D
    `sqrt(k) xx r`
  • If the velocity of a particle is given by v=(180-16x)^((1)/(2))(m)/(s) , then its acceleration will be

    A
    zero
    B
    `8(m)/(s^2)`
    C
    `-8(m)/(s^2)`
    D
    `4(m)/(s^2)`
  • The displacement of body is given by s = 4 + 2t^4 . The acceleration of the body at the end of 1 s from the start is :

    A
    `24 m//"sec"^(2)`
    B
    `10 m//"sec"^(2)`
    C
    `15 m//"sec"^(2)`
    D
    `12 m//"sec"^(2)`
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