A free electron of 2.6 eV energy collide...

A free electron of 2.6 eV energy collides with a `H^(+)` ion .This results in the formation of a hydrogen atom in the first excited state and photon is relased .Find the frequency of the emitted photon `(h=6.6xx10^(-34))`Js

`1.45xx10^(16)MHz`

`1.45xx10^(9)MHz`

`0.19xx10^(15)MHz`

`9.0xx10^(27)MHz`

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