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The magnetic field vector of an electrom...

The magnetic field vector of an electromagnetic wave is given by `B=B_(0)(hat(i)+hatj)/(sqrt(2))cos(kz-omegat)`, where `hati,hatj` represents unit vector along x and y - axis repectively .At t=0 s , two electric charges `q_(1)`of `4pi` coulomb and `q_(2)` of `2pi` coulmb located at `(0,0,(pi)/(k))and(0,0,(3pi)/(k))`, repectively ,have the same velocity of `0.5chati` ,(where c is the velocity of light ).The ratio of the force actig on charge `q_(1)` to `q_(2)` is :

A

`2 :1`

B

`2sqrt(2):1`

C

`1:sqrt(2)`

D

`sqrt(2):1`

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