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B(1) is a point on the side AC of Delta...

`B_(1)` is a point on the side AC of `DeltaABC` and `B_(1)B` is joined. A line is drawn through a parallel to `B_(1)B` meeting BC at `A_(1)` and another line is drawn through C parallel to `B_(1)B` meeting AB produced at `C_(1)` The

A

`(1)/(C C_1)-(1)/(A A_1)=(1)/(B B_1)`

B

`(1)/(C C_1)+(1)/(A A_1)=(1)/(B B_1)`

C

`(1)/(B B_1)-(1)/(A A_1)=(1)/(C C_1)`

D

`(1)/(A A_1)-(1)/(C C_1)=(1)/(B B_1)`

Text Solution

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The correct Answer is:
B
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