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ABCD is a trapezium. Sides AB and CD. ar...

ABCD is a trapezium. Sides AB and CD. are parallel to each other.AB=6 cm, CD=18cm, BC=8cm and AD=12cm. A line parallel to AB divides the trapezium in two parts of equal perimeter. This line cuts BC at E and AD at F. If BE/EC = AF/FD, than what is the value of BE/EC?
ABCD एक सम्लम्ब चतुर्भज है। भुजाएँ AB तथा CD एक दूसरे के समान्तर है। AB=6 सेमी. CD=18 सेमी. BC=8 सेमी. तथा AD= 12 सेमी. है। AB के समान्तर एक रेखा सम्लम्ब को दी बराबर परिमाप वाले हिस्से में काटता है। यह रेखा भुजा BC को E पर तथा AD को F पर काटती है। यदि BE/EC=AF/FD है, तो BE/EC का मान क्या है?

A

`1//2`

B

`2`

C

`4`

D

`1//4`

Text Solution

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The correct Answer is:
D
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