Home
Class 14
MATHS
DeltaABC is an isosceles right angled tr...

`DeltaABC` is an isosceles right angled triangle having `angleC=90^(@)`. If D is any point on AB, then `AD^(2)+BD^(2)` is equal to

A

`CD^2`

B

`2CD^2`

C

`3CD^2`

D

`4 CD^2`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

ABC is a isosceles right angled triangle, right angled at C. prove that AB^(2) = 2AC^(2)

In a right-angled triangle ABC, angleC = 90^(@) and CD is perpendicular to AB. If AB x CD = CA x CB, then 1/(CD^(2)) is equal to:

ABC is a right angled triangle in which angleB=90^(@) and AB=BC . Find angleA and angleC .

ABC is a right-angled triangled, right angled at A*AD is drawn perpendicular to BC from A . Then AB^2 is equal to

In the given figure ABC is a right angled triangle with angleB=90^(@) . D is the mid -point of BC . Show that AC^(2) = AD^(2) +3CD^(2) .

In an isosceles right angled triangle ABC , /_B=90^(0) , AD is the median, then (sin/_BAD)/(sin/_CAD) is

ABC is a right angled isosceles triangle with /_B=90^(@) If D is a point on AB such that /_CDB=15^(@) and ifAD=35cm then CD is equal to

ABC is an isosceles right triangle right- angled at C. Prove that AB^(2)=2AC^(2)