Home
Class 14
MATHS
In DeltaABC,D and E are the mid points o...

In `DeltaABC,D` and E are the mid points of sides BC and AC respectively. If `AD=10.8` cm, BE `=14.4` cm and AD and BE intersect at G at a right angle then the area `("in cm"^(2))` of `DeltaABC` is :

A

A)`103.68`

B

B)`56.76`

C

C)`80.64`

D

D)`53.76`

Text Solution

AI Generated Solution

The correct Answer is:
To find the area of triangle ABC given the midpoints D and E, and the lengths of the medians AD and BE, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Information:** - Length of median AD = 10.8 cm - Length of median BE = 14.4 cm - AD and BE intersect at point G at a right angle. 2. **Understand the Properties of Medians:** - In triangle ABC, D is the midpoint of side BC, and E is the midpoint of side AC. - The medians AD and BE intersect at the centroid G of the triangle. 3. **Use the Area Formula for Triangle with Medians:** - The area of triangle ABC can be calculated using the formula: \[ \text{Area} = \frac{2}{3} \times AD \times BE \] - This formula applies when the medians intersect at a right angle. 4. **Substitute the Values:** - Substitute the values of AD and BE into the formula: \[ \text{Area} = \frac{2}{3} \times 10.8 \times 14.4 \] 5. **Calculate the Area:** - First, calculate the product of the medians: \[ 10.8 \times 14.4 = 155.52 \] - Now, substitute this product into the area formula: \[ \text{Area} = \frac{2}{3} \times 155.52 \] - Calculate: \[ \text{Area} = \frac{311.04}{3} = 103.68 \text{ cm}^2 \] 6. **Final Result:** - The area of triangle ABC is \( 103.68 \text{ cm}^2 \).
Promotional Banner

Similar Questions

Explore conceptually related problems

In triangle ABC,D and E are mid points of sides Bc and AC, respectively. If AD = 10.8 cm, BE=14.4 cm nad Ad and BE intersect at G at a right angle, thent he area (in cm^2 ) of triangle ABC is: triangle ABC में D और E क्रमशः भुजा BC और AC के मध्य बिंदु है । यदि AD=10.8 cm, BE =14.4 cm और AD और BE समकोण पर G पर प्रतिच्छेदित करते हैं, तो triangle ABC का क्षेत्रफल ( cm^2 में) ज्ञात कीजिए।

In angle ABC , D and E are the midpoint of sides BC and AC, respectively AD and BE intersect at G at right angle. If AD= 18cm and BE = 12cm then the length of DC (in cm) is : त्रिभुज ABC में, D और E भुजाओं BC और AC के मध्य बिंदु हैं, क्रमश AD और BE समकोण पर G पर प्रतिच्छेद करते ह। यदि AD = 18 सेमी और BE = 12 सेमी तो DC (सेमी में) की लंबाई है:

In DeltaABC , D and E are points on sides AB and AC respectively such that DE||BC . If AE=1.8cm, BD= 7.2cm and CE= 5.4cm, then the length of AD is

In DeltaABC,D and E are points on the sides AB and AC respectively ,such that DE||BC. If AD=2.5cm,BD=3cm and AE =3.75 cm , then the value of AC.

If D and E are the mid points of AB and AC respectively of DeltaABC , then the ratio of the areas of ADE and BCED is?

Points D, E and F are the midpoints of sides AB, BC, and AC of DeltaABC . If DE = 10 cm, EF = 12 cm and DF = 8 cm, then find AB.

In DeltaABC, angleC=90^(@) . M and N are the mid-points of sides AB and AC,respectively. CM and BN intersect each other at D and angleBDC=90^(@). If BC=8cm, then length of BN is :

D and E are the points on the sides AB and AC respectively of a ABC such that: AD=8cm,quad DB=12cm,quad AE=6cm and CE=9cm. Prove that BC=5/2DE