Home
Class 14
MATHS
If A=(0.216 +0.008)/(0.36+0.04-0.12) and...

If `A=(0.216 +0.008)/(0.36+0.04-0.12)` and `B=(0.729 - 0.027)/(0.81+ 0.09 +0.27)`, then what is the value of `(A^2+B^2)^2` ?

A

`0.8`

B

1

C

`1.4`

D

`2.2`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

(0.125 + 0.027)/(0.25 - 0.15 + 0.09) is equal to

0.09 xx 0.008 = ?

0.04 // 0.2 = 0.2

If A =((0.1)^3+(0.2)^3+(0.3)^3+3(0.005 + 0.016 + 0.027) + 0.036)/((0.1)^2+(0.2)^2+ (0.3)^2+0.04 + 0.06 + 0.12) ,then the value of 60A is: यदि A =((0.1)^3+(0.2)^3+(0.3)^3+3(0.005 + 0.016 + 0.027) + 0.036)/((0.1)^2+(0.2)^2+ (0.3)^2+0.04 + 0.06 + 0.12) है, तो 60A का मान क्या होगा ?

The vlaue of (64 - 0.008)/(16 + 0.8 + 0.04) is

To find out the concentrations of S O_2 in the air (in parts per million, i.e., ppm), the data was collected for 30 localities in a certain city and is presented below: Concentration of S O_2 (in ppm) Frequency 0.00 - 0.04 4 0.04 - 0.08 9 0.08 - 0.12 9 0.12 - 0.16 2 0.16 - 0.20 4 0.20 - 0.24 2 Find the mean concentration of S O_2 in the air.