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If x+(16)/(x)=8, then the value of x^2+(...

If `x+(16)/(x)=8`, then the value of `x^2+(32)/(x^2)` is:

A

24

B

18

C

20

D

16

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( x + \frac{16}{x} = 8 \) and find the value of \( x^2 + \frac{32}{x^2} \), we can follow these steps: ### Step 1: Rearrange the given equation Start with the equation: \[ x + \frac{16}{x} = 8 \] Multiply both sides by \( x \) to eliminate the fraction: \[ x^2 + 16 = 8x \] ### Step 2: Rearrange into standard quadratic form Rearranging gives us: \[ x^2 - 8x + 16 = 0 \] ### Step 3: Factor the quadratic equation This quadratic can be factored as: \[ (x - 4)^2 = 0 \] Thus, we find: \[ x - 4 = 0 \implies x = 4 \] ### Step 4: Substitute \( x \) to find \( x^2 + \frac{32}{x^2} \) Now that we have \( x = 4 \), we can substitute this value into the expression we want to find: \[ x^2 + \frac{32}{x^2} \] Calculating \( x^2 \): \[ x^2 = 4^2 = 16 \] Now calculate \( \frac{32}{x^2} \): \[ \frac{32}{x^2} = \frac{32}{16} = 2 \] ### Step 5: Add the two results Now, add the two results together: \[ x^2 + \frac{32}{x^2} = 16 + 2 = 18 \] ### Final Answer Thus, the value of \( x^2 + \frac{32}{x^2} \) is: \[ \boxed{18} \] ---
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