If a^(2)sec^(2)x-b^(2)tan^(2)x=c^(2) ...

If `a^(2)sec^(2)x-b^(2)tan^(2)x=c^(2)` then the value of `(sec^(2)x+tan^(2)x)` is equal to (assume `b^(2)nea^(2))`

A

`(b^(2)-a^(2)+2c^(2))/(b^(2)+a^(2))`

B

`(b^(2) +a^(2)-2c^(2))/(b^(2)-a^(2))`

C

`(b^(2)-a^(2) -2c^(2))/(b^(2)+a^(2))`

D

`(b^(2)-a^(2))/(b^(2)+a^(2)+2c^(2))`

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The correct Answer is:

A, B, C

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